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Chemia Fizyczna test 1

Test w formie fiszek
Ilość pytań: 14 Rozwiązywany: 2720 razy
For a perfect gas:
Molar entropy does not depend on pressure
the enthalpy does not depend on pressure
pV is proportional to absolute temperature
Molar entropy always increases with temprerature
Cv=Cp-nR
the enthalpy does not depend on pressure
pV is proportional to absolute temperature
Cv=Cp-nR
For a perfect gas:
Molar entropy does not depend on pressure
the enthalpy does not depend on pressure
pV is proportional to absolute temperature
Molar entropy always increases with temprerature
Cv=Cp-nR
In a reversible adiabatic process:
ΔU=w
ΔT=0
ΔU=w but only for perfect gas
q+w=TΔS
ΔU=ΔH+Δ(pV) but only for perfect gas
ΔU=w
In a reversible adiabatic process:
ΔU=w
ΔT=0
ΔU=w but only for perfect gas
q+w=TΔS
ΔU=ΔH+Δ(pV) but only for perfect gas
The standard enthalpy of combustion of a compound:
is equal to TΔcSo+ΔcGo
doesn’t depend on temperature
is the the heat effect of reaction of combustion of 1 mole of a compound in air at standard pressure
is defined at standard pressure
is equal to TΔcSo+ΔcGo
is defined at standard pressure
The standard enthalpy of combustion of a compound:
is equal to TΔcSo+ΔcGo
doesn’t depend on temperature
is the the heat effect of reaction of combustion of 1 mole of a compound in air at standard pressure
is defined at standard pressure
The entropy change in an isothermal decompression of a perfect gas against constant pressure p_ext
is equal to -delta(pV)/T
is equal to (C_v razy delta T)/T
is equal to delta(pV)/T
is equal to zero
none from above
none from above
The entropy change in an isothermal decompression of a perfect gas against constant pressure p_ext
is equal to -delta(pV)/T
is equal to (C_v razy delta T)/T
is equal to delta(pV)/T
is equal to zero
none from above
In first order phase transition:
The transition entropy is delta H=T delta trans S
Entropy changes in continous way
thermal expresion coefficient shows a discontinuity
Entropy shows a discontinuity
The heat capacity shows a discontinuity
thermal expresion coefficient shows a discontinuity
Entropy shows a discontinuity
The heat capacity shows a discontinuity
In first order phase transition:
The transition entropy is delta H=T delta trans S
Entropy changes in continous way
thermal expresion coefficient shows a discontinuity
Entropy shows a discontinuity
The heat capacity shows a discontinuity
The chemical potential μi:
doesn’t depend on pressure
can be defined as (dG/dξ)T
always increases with temperature
at the triple point of a substance is equal for solid, liquid and vapor
has a minimum at the critical point
at the triple point of a substance is equal for solid, liquid and vapor
The chemical potential μi:
doesn’t depend on pressure
can be defined as (dG/dξ)T
always increases with temperature
at the triple point of a substance is equal for solid, liquid and vapor
has a minimum at the critical point
the enthopy of mixing:
is equal to RTlnx in system (henry's law)
is equal to Rlnx in system (henry's law)
is 0 for perfect gases
is equal to -RTlnx in system (raoult's law)
is equal to -Rlnx in system (raoult's law)
is equal to -Rlnx in system (raoult's law)
the enthopy of mixing:
is equal to RTlnx in system (henry's law)
is equal to Rlnx in system (henry's law)
is 0 for perfect gases
is equal to -RTlnx in system (raoult's law)
is equal to -Rlnx in system (raoult's law)
The thermodynamic equilibrium constant K:
does not depend on temperature
does not depend on the total volume of the reaction mixture
depends on the partial pressures in the reaction mixture
has a temperature dependence given by the Van’t Hoff law
depends on the molar fractions of reactants and products in the mixture
does not depend on the total volume of the reaction mixture
has a temperature dependence given by the Van’t Hoff law
The thermodynamic equilibrium constant K:
does not depend on temperature
does not depend on the total volume of the reaction mixture
depends on the partial pressures in the reaction mixture
has a temperature dependence given by the Van’t Hoff law
depends on the molar fractions of reactants and products in the mixture
How many degrees of freedom would have:
sulphur vapor in equilibrium with orthorombic sulphur and monochromic sulphur 0
A two-compontnt system with two phases 2
A three-component system with 3 phases if temperature and pressure are fixed 0
ice in water at 1atm 0
How many degrees of freedom would have:
For the concentration cell Ag|Ag+(c1)||Ag+(c2)|Ag
ΔrG=0
emf is positive if c2>c1
ΔrG=0
ΔrS⊕ > 0 for c2>c1
Emf is equal to zero for c2=c1
emf is positive if c2>c1
For the concentration cell Ag|Ag+(c1)||Ag+(c2)|Ag
ΔrG=0
emf is positive if c2>c1
ΔrG=0
ΔrS⊕ > 0 for c2>c1
Emf is equal to zero for c2=c1
The mobility of H+ ions in sulphuric acid solutions:
is equal to 2tH+ ΛH2SO4
increases with temperature
decreases with temperature
decreases with the acid concentration
increases with temperature
decreases with the acid concentration
The mobility of H+ ions in sulphuric acid solutions:
is equal to 2tH+ ΛH2SO4
increases with temperature
decreases with temperature
decreases with the acid concentration
The rate of reaction 2A+B->3C is equal to:
-k[C]^3
k[C]^3
2 d[A]/dt + d[B]/dt
1/3d[C]/dt
3 d[C] /dt
1/3d[C]/dt
The rate of reaction 2A+B->3C is equal to:
-k[C]^3
k[C]^3
2 d[A]/dt + d[B]/dt
1/3d[C]/dt
3 d[C] /dt
In second-order reaction (nie pamiętam równania)
t ½ jest odwrotnie proporcjonalny do [A]
zależy od [A]^2
t ½ nie zależy od temperatury
t ½ jest odwrotnie proporcjonalny do [A]
In second-order reaction (nie pamiętam równania)
t ½ jest odwrotnie proporcjonalny do [A]
zależy od [A]^2
t ½ nie zależy od temperatury
In reactions A+B---(k1)--->C 2C---(k2)--->D k2>>k1 Therefore:
rate of formation of [D] is approx. first order in [A]
the steady-state approx. can be used for [C]
[D] =~ (k2)/(2k1) * [C]
the steady-state approx. cannot be used for [B]
d[D]/dt =~ (k1k2)/(k1+k2) * [A][B]
the steady-state approx. can be used for [C]
the steady-state approx. cannot be used for [B]
In reactions A+B---(k1)--->C 2C---(k2)--->D k2>>k1 Therefore:
rate of formation of [D] is approx. first order in [A]
the steady-state approx. can be used for [C]
[D] =~ (k2)/(2k1) * [C]
the steady-state approx. cannot be used for [B]
d[D]/dt =~ (k1k2)/(k1+k2) * [A][B]
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